47k^2+6k=0

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Solution for 47k^2+6k=0 equation: 



47k^2+6k=0

a = 47; b = 6; c = 0;
Δ = b2-4ac
Δ = 62-4·47·0
Δ = 36
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$k_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$k_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{36}=6$


$k_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(6)-6}{2*47}=\frac{-12}{94}
=-6/47
$


$k_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(6)+6}{2*47}=\frac{0}{94}
=0
$

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